➕ Algebra 1 · Linear Functions

Standard Form of a Line: notes and common mistakes

Study notes

Key ideas

  • Standard form is Ax + By = C, with A and B not both 0. The graph is a straight line.
  • The usual convention is integers for A, B and C, with A not negative and no common factor. It is a convention, not a law of math.
  • Cover the y term to find the x-intercept C/A (if A ≠ 0). Cover the x term to find the y-intercept C/B (if B ≠ 0).
  • To get slope-intercept form, solve for y. The slope is −A/B and the y-intercept is C/B (if B ≠ 0).
  • A = 0 gives a horizontal line. B = 0 gives a vertical line, which standard form can write but slope-intercept form cannot.
  • Standard form fits totals of two quantities: price × number for each item, added to a fixed total.

Steps

  1. To find intercepts: cover the y term and solve for x, then cover the x term and solve for y.
  2. To graph: plot the two intercept points, draw the line through them, and check a third point.
  3. To reach slope-intercept form: subtract the x term, then divide every term by B.
  4. To reach standard form: clear fractions, move the x and y terms to the left and the number to the right, make A not negative, and remove any common factor.

Formulas

  • Standard form: Ax + By = C, with A and B not both 0
  • x-intercept: x = C/A (if A ≠ 0), so the line crosses at (C/A, 0)
  • y-intercept: y = C/B (if B ≠ 0), so the line crosses at (0, C/B)
  • Slope: m = −A/B (if B ≠ 0)
  • Horizontal line: A = 0: y = C/B, slope 0
  • Vertical line: B = 0: x = C/A, slope undefined

Watch out

  • Signs belong to their numbers: in 2x − 5y = 10, B = −5.
  • The slope is −A/B, with a minus sign. It is not A/B.
  • To find the x-intercept, set y = 0 (cover the y term). Setting x = 0 finds the y-intercept.
  • When you divide by a negative B, every term changes sign. Divide every term, not just one.
  • If C = 0, both intercepts are 0 and the line crosses both axes at (0, 0), so you need another point.

Why it works

  • Why cover a term? The x-axis has y = 0, so the y term becomes 0 and disappears. The y-axis has x = 0, so the x term disappears.
  • Why is the slope −A/B? Solving Ax + By = C for y gives y = −(A/B)x + C/B, and the number multiplying x is the slope.
  • Why can you multiply every term by a number that is not 0? Doing the same thing to both sides keeps the same solutions, so the graph does not change. Multiplying by 0 would destroy the equation.

Common mistakes

✗ MistakeIn 2x − 5y = 10, B is 5.
✓ InsteadThe minus sign belongs to the 5, so B = −5. The equation means 2x + (−5)y = 10.
✗ MistakeThe slope of 3x + 2y = 12 is 3/2.
✓ InsteadSolving for y gives y = −(3/2)x + 6, so the slope is −3/2. In general the slope is −A/B.
✗ MistakeTo find the x-intercept, set x = 0.
✓ InsteadThe x-intercept is where the line crosses the x-axis, where y = 0. Cover the y term and solve for x. Setting x = 0 finds the y-intercept.
✗ MistakeStandard form is a law: 6x + 4y = 24 is wrong because 3x + 2y = 12 is the real standard form.
✓ InsteadBoth equations have the same graph. Writing integers with A not negative and no common factor is a convention that picks one tidy version. Follow your teacher’s version when one is required.
✗ MistakeA vertical line cannot be written in standard form because its slope is undefined.
✓ InsteadIt can: x = 3 is 1x + 0y = 3. Standard form writes every line. It is slope-intercept form that cannot write a vertical line.

Teach it back

Explain to a friend how to graph 6x + 5y = 30 using the intercepts, how to write it in slope-intercept form, and how to check that (−5, 12) is on the line.

Explaining it out loud shows what you really know. Did you…

  • I covered the y term to get 6x = 30, so the x-intercept is 5 and the line crosses at (5, 0). I covered the x term to get 5y = 30, so the y-intercept is 6 and the line crosses at (0, 6).
  • I subtracted 6x and divided every term by 5 to get y = −(6/5)x + 6, so the slope is −6/5.
  • I checked (−5, 12) by substituting: 6(−5) + 5(12) = −30 + 60 = 30, so it is on the line.

Your 3-week memory plan

  1. TodayRead the lesson, then try the flashcards.
  2. TomorrowRecall it from memory first, then check.
  3. In 3 daysTake the true/false and practice questions.
  4. In 1 weekMix it with older topics and teach it back.
  5. In 3 weeksA last quick review before it fades.

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